If it's not what You are looking for type in the equation solver your own equation and let us solve it.
60x^2-35x=0
a = 60; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·60·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*60}=\frac{0}{120} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*60}=\frac{70}{120} =7/12 $
| 7x/2+1/2=11 | | 7x-)-8=5x+6 | | 2(x-2)=8x-9-6x | | 6.6x-2.6=4.0 | | 2z+3=31 | | 3+2z=13 | | 7-4y=8-9y+5y | | 3x+41=85 | | 4x+31=79 | | 126+x=146+x+24=180 | | 3x+34=8 | | 126+x=146+x+26=180 | | 4(5y)-y=79 | | 0.25x+0.5x+x+x+3=300 | | -(n-9)=3n+17 | | 126+x=146+x+26 | | 1/4x+1/2x+x+x+3=300 | | 48r-9=9(5r+2) | | 2x^2=-7 | | 4x-8=-3x^2 | | y+6-2=11 | | -9x+3(4x-1)=-81 | | 4x.3=7-x | | (4x+1)+(7x+3)+65=x | | (4x+1)+(7x+3)=x | | (-x+1)/6-(5-3x)/4=1/3 | | 40x+9=30 | | 30x+5=10x | | -3=7.3+n/2 | | 2x+4x=-(-7x+6) | | 1/5(x-10)=5 | | 8y-6=5y=12 |